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Download : Engineering_Fundamentals_of_Heat_and_Mass_Transfer_[Frank_PIncropera_-_David_PDeWitt]_Solution_Manual[2].pdf






열전달 6판입니다. 전범위 解法(솔루션) 입니다




Engineering Fundamentals of Heat and Mass Transfer [Frank PIncropera David PDeWitt] Solution Manual 解法(솔루션)
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Engineering_Fundamentals_of_Heat_and_Mass_Transfer_[Frank_PIncropera_-_David_PDeWitt]_Solution_Manual[2]_pdf_01.gif Engineering_Fundamentals_of_Heat_and_Mass_Transfer_[Frank_PIncropera_-_David_PDeWitt]_Solution_Manual[2]_pdf_02.gif Engineering_Fundamentals_of_Heat_and_Mass_Transfer_[Frank_PIncropera_-_David_PDeWitt]_Solution_Manual[2]_pdf_03.gif Engineering_Fundamentals_of_Heat_and_Mass_Transfer_[Frank_PIncropera_-_David_PDeWitt]_Solution_Manual[2]_pdf_04.gif Engineering_Fundamentals_of_Heat_and_Mass_Transfer_[Frank_PIncropera_-_David_PDeWitt]_Solution_Manual[2]_pdf_05.gif Engineering_Fundamentals_of_Heat_and_Mass_Transfer_[Frank_PIncropera_-_David_PDeWitt]_Solution_Manual[2]_pdf_06.gif

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Download : Engineering_Fundamentals_of_Heat_and_Mass_Transfer_[Frank_PIncropera_-_David_PDeWitt]_Solution_Manual[2].pdf( 44 )



PROBLEM 1.1 KNOWN: Heat rate, q, through one-dimensional wall of area A, thickness L, thermal
conductivity k and inner temperature, T1. FIND: The outer temperature of the wall, T2. SCHEMATIC:

ASSUMPTIONS: (1) One-dimensional conduction in the x-direction, (2) Steady-state conditions, (3) Constant properties. ANALYSIS: The rate equation for conduction through the wall is given by Fourier’s law,

q cond = q x = q ′′ ? A = -k x
Solving for T2 gives

T ?T dT ? A = kA 1 2 . dx L

T2 = T1 ?

q cond L . kA

Substituting numerical values, find

T2 = 415 C -

3000W × 0.025m 0.2W / m ? K × 10m2

T2 = 415 C - 37.5 C T2 = 378 C.
COMMENTS: Note direction of heat flow and fac…(skip)


열전달,heat,transfer,물리,솔루션



다. 전범위 솔루션입니다 , Engineering Fundamentals of Heat and Mass Transfer [Frank PIncropera David PDeWitt] Solution Manual 솔루션물리솔루션 , 열전달 heat transfer
열전달 6판입니다.

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